General Topology Problem Solution Engelking -

General Topology Problem Solution Engelking**

Next, we show that A ⊆ cl(A). Let a be a point in A. Then every open neighborhood of a intersects A, and hence a ∈ cl(A). General Topology Problem Solution Engelking

Finally, we show that cl(A) is the smallest closed set containing A. Let F be a closed set containing A. We need to show that cl(A) ⊆ F. Let x be a point in cl(A). Suppose x ∉ F. Then x ∈ X F, which is open. This implies that there exists an open neighborhood U of x such that U ⊆ X F. But then U ∩ A = ∅, which contradicts the fact that x ∈ cl(A). Therefore, x ∈ F, and cl(A) ⊆ F. Let X be a topological space and let {Aα} be a collection of subsets of X. Show that ∪α cl(Aα) ⊆ cl(∪α Aα). General Topology Problem Solution Engelking** Next, we show